In this problem, we're going to use the law of conservation of angular momentum, stated as:
The moment of inertia of the door is given by:
Idoor = (1/3)Mr2 = (1/3)(43.0)(12) = 14.33 kg•m2
A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 43.0 kg . Initially open and at rest, the door is struck at its center by a handful of sticky mud with mass 0.600 kg , traveling perpendicular to the door at 13.0 m/s just before impact.
Find the final angular speed of the door.
Does the mud make a significant contribution to the moment of inertia?
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