Collisions with Springs Video Lessons

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Problem: A 15.0 kg block is attached to a very light horizontal spring of force constant 475 N/m and is resting on a smooth horizontal table. (See the figure below .) Suddenly it is struck by a 3.00 kg stone traveling horizontally at 8.00 m/s to the right, whereupon the stone rebounds at 2.00 m/s horizontally to the left.Find the maximum distance that the block will compress the spring after the collision.(Hint: Break this problem into two parts - the collision and the behavior after the collision - and apply the appropriate conservation law to each part.)

FREE Expert Solution

The conservation of linear momentum equation:

m1v01+m2v02=m1vf1+m2vf2

We'll also use the law of conservation of energy:

Ki+Ui+Wnc=Kf+Uf, where Wnc is the work done by non-conservative forces such as friction.

For our case, Ui = 0 since there is no height (Remember U = mgh).

Wnc = 0 because there is no friction or any other non-conservative forces (we're told that the spring is on a smooth horizontal table).

After the collision, we do not have kinetic energy since the spring will be at rest.

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Problem Details

A 15.0 kg block is attached to a very light horizontal spring of force constant 475 N/m and is resting on a smooth horizontal table. (See the figure below .) Suddenly it is struck by a 3.00 kg stone traveling horizontally at 8.00 m/s to the right, whereupon the stone rebounds at 2.00 m/s horizontally to the left.

Find the maximum distance that the block will compress the spring after the collision.(Hint: Break this problem into two parts - the collision and the behavior after the collision - and apply the appropriate conservation law to each part.)

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