The position of a 260 g object is given (in meters) by x = 5.0t3 - 8.0t2 - 45t, where t is in seconds.
(a) Determine the net rate of work done on this object at t =2.1 s.
(b) Determine the net rate of work done on this object at t = 4.1 s.
(c) What is the average net power input during the interval from t = 0 to t = 2.1 s?
(d) What is the average net power input during the interval from t =2.1 s to t=4.1 s?
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