We'll use the kinematic equation:

$\overline{){\mathbf{\u2206}}{\mathbf{y}}{\mathbf{=}}{{\mathbf{v}}}_{{\mathbf{0}}}{\mathbf{t}}{\mathbf{-}}\frac{\mathbf{1}}{\mathbf{2}}{\mathbf{g}}{{\mathbf{t}}}^{{\mathbf{2}}}}$

Consider the conservation of energy:

$\overline{){\mathbf{\u2206}}{\mathbf{U}}{\mathbf{=}}{\mathbf{\u2206}}{\mathbf{K}}}$

The block is starting from rest, so v_{0 }= 0

A 2.8-kg block slides over the smooth, icy hill shown in the figure.

The top of the hill is horizontal and 70 m higher than its base.

What minimum speed must the block have at the base of the 70-m hill to pass over the pit at the far (righthand) side of that hill?

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