Kinetic energy is found from the formula:

$\overline{){\mathbf{K}}{\mathbf{=}}\frac{\mathbf{1}}{\mathbf{2}}{{\mathbf{mv}}}^{{\mathbf{2}}}}$

**a.**

The maximum speed of the particle is found when the potential energy, U is minimum.

Potential energy, U is minimum at x = 4m where U = 1 J

Applying the law of conservation of energy between points 4 and 1,

is the potential-energy diagram for a 20 g particle that is released from rest at x = 1.0 m.

a. What is the particles maximum speed? At what position does it have this speed?

b. Where are the turning points of the motion?

c. Will the particle move to the right or to the left?

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