Ch 25: Electric Force & Field; Gauss' LawWorksheetSee all chapters
All Chapters
Ch 01: Intro to Physics; Units
Ch 02: 1D Motion / Kinematics
Ch 03: Vectors
Ch 04: 2D Kinematics
Ch 05: Projectile Motion
Ch 06: Intro to Forces (Dynamics)
Ch 07: Friction, Inclines, Systems
Ch 08: Centripetal Forces & Gravitation
Ch 09: Work & Energy
Ch 10: Conservation of Energy
Ch 11: Momentum & Impulse
Ch 12: Rotational Kinematics
Ch 13: Rotational Inertia & Energy
Ch 14: Torque & Rotational Dynamics
Ch 15: Rotational Equilibrium
Ch 16: Angular Momentum
Ch 17: Periodic Motion
Ch 19: Waves & Sound
Ch 20: Fluid Mechanics
Ch 21: Heat and Temperature
Ch 22: Kinetic Theory of Ideal Gasses
Ch 23: The First Law of Thermodynamics
Ch 24: The Second Law of Thermodynamics
Ch 25: Electric Force & Field; Gauss' Law
Ch 26: Electric Potential
Ch 27: Capacitors & Dielectrics
Ch 28: Resistors & DC Circuits
Ch 29: Magnetic Fields and Forces
Ch 30: Sources of Magnetic Field
Ch 31: Induction and Inductance
Ch 32: Alternating Current
Ch 33: Electromagnetic Waves
Ch 34: Geometric Optics
Ch 35: Wave Optics
Ch 37: Special Relativity
Ch 38: Particle-Wave Duality
Ch 39: Atomic Structure
Ch 40: Nuclear Physics
Ch 41: Quantum Mechanics
Electric Charge
Charging Objects
Charging By Induction
Conservation of Charge
Coulomb's Law (Electric Force)
Electric Field
Electric Fields in Capacitors
Electric Field Lines
Dipole Moment
Electric Fields in Conductors
Electric Flux
Gauss' Law

Practice: The electric flux through each surface of a cube is given below. Which surfaces of the cube does the electric field run parallel to? 

Φ1 = 100 Nm2 /C           Φ4 = 0 Nm2 /C
Φ2 = 20 Nm2 /C             Φ5 = −40 Nm2 /𝐶
Φ3 = 0 Nm2 /C               Φ6 = −80 Nm2 /𝐶

Example #1: Flux Through Angled Surface

Example #2: Flux Through Cube

Practice: Where does the normal vector point for a spherical shell?

Example #3: Flux Through Spherical Shell due to Point Charge

Practice: What is the total flux through the two surfaces depicted in the following figure? Note that surface 1 has an area of 50 cm2 and surface 2 has an area of 100 cm2 , and E = 500 N/C.