The compounds n-butane, CH3(CH2)2CH3 and trimethylamine, N(CH3)3 have very similar molecular weights. However, their melting points are appreciably different. Select the compound with the lowest melting point, and the correct reason why.
a. trimethylamine, because it will experience dipolar forces between molecules
b. n-butane, because it is unbranched
c. trimethylamine, because it is more highly O branched than n-butane
d. n-butane, because it will only experience dispersion forces between molecules
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