Problem: Given that (S)-2-butanol has a specific rotation of +13.52 o and (R)-2-butanol has a specific rotation of -13.52o, what is % composition of a mixture whose specific rotation was found to be +6.76o? A) 75%(R) 25%(S)B) 25%(R) 75%(S)C) 50%(R) 50%(S)D) 67%(R) 33%(S)E) 33%(R) 67%(S)

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Given that (S)-2-butanol has a specific rotation of +13.52 and (R)-2-butanol has a specific rotation of -13.52o, what is % composition of a mixture whose specific rotation was found to be +6.76o?

A) 75%(R) 25%(S)

B) 25%(R) 75%(S)

C) 50%(R) 50%(S)

D) 67%(R) 33%(S)

E) 33%(R) 67%(S)

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Our tutors have indicated that to solve this problem you will need to apply the Calculations with Enantiomeric Percentages concept. You can view video lessons to learn Calculations with Enantiomeric Percentages. Or if you need more Calculations with Enantiomeric Percentages practice, you can also practice Calculations with Enantiomeric Percentages practice problems.

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Based on our data, we think this problem is relevant for Professor Daoudi's class at UCF.