Ch. 6 - Thermodynamics and KineticsWorksheetSee all chapters
All Chapters
Ch. 1 - A Review of General Chemistry
Ch. 2 - Molecular Representations
Ch. 3 - Acids and Bases
Ch. 4 - Alkanes and Cycloalkanes
Ch. 5 - Chirality
Ch. 6 - Thermodynamics and Kinetics
Ch. 7 - Substitution Reactions
Ch. 8 - Elimination Reactions
Ch. 9 - Alkenes and Alkynes
Ch. 10 - Addition Reactions
Ch. 11 - Radical Reactions
Ch. 12 - Alcohols, Ethers, Epoxides and Thiols
Ch. 13 - Alcohols and Carbonyl Compounds
Ch. 14 - Synthetic Techniques
Ch. 15 - Analytical Techniques: IR, NMR, Mass Spect
Ch. 16 - Conjugated Systems
Ch. 17 - Aromaticity
Ch. 18 - Reactions of Aromatics: EAS and Beyond
Ch. 19 - Aldehydes and Ketones: Nucleophilic Addition
Ch. 20 - Carboxylic Acid Derivatives: NAS
Ch. 21 - Enolate Chemistry: Reactions at the Alpha-Carbon
Ch. 22 - Condensation Chemistry
Ch. 23 - Amines
Ch. 24 - Carbohydrates
Ch. 25 - Phenols
Ch. 26 - Amino Acids, Peptides, and Proteins

Solution: When 2-methylbutene is reacted with hydrochloric acid, where does the carbocation form and why? 1. The carbocation forms at the tertiary position because of steric hindrance. 2. The carbocation forms at the secondary position because of hyperconjugation from neighboring carbons. 3. The carbocation forms at the primary position because nature says so. 4. The carbocation forms at the tertiary position because of hyperconjugation from neighboring carbons.

Problem

When 2-methylbutene is reacted with hydrochloric acid, where does the carbocation form and why?

1. The carbocation forms at the tertiary position because of steric hindrance.

2. The carbocation forms at the secondary position because of hyperconjugation from neighboring carbons.

3. The carbocation forms at the primary position because nature says so.

4. The carbocation forms at the tertiary position because of hyperconjugation from neighboring carbons.