Solution: True/False. Identify the statements as either True or False.    Reduction of an alkyne to an alkene with sodium metal in liquid ammonia is a partial radical mechanism. In polar protic solvents a selenide anion (Se-2) is a stronger nucleophile as compared to a sulfide anion (S-2). The leaving group and the departing hydrogen in an E2 elimination reaction has to be on the same side. Halogens have lower priority as compared to alkenes in IUPAC naming system. The rate of a SN1 reaction increases with increasing carbocation stability. Sodium hydroxide is a strong base and can be used to deprotonate terminal alkynes in a 100% yield. Carbocations form tight ion-pairs with halide anion. In SN2 reactions the rate-determining step involves two molecules. Iodine is a better leaving group than fluorine because iodine is more polarizable than fluorine.  Vinylic carbocations can undergo carbocation rearrangement.

Problem

True/False. Identify the statements as either True or False. 

 

Reduction of an alkyne to an alkene with sodium metal in liquid ammonia is a partial radical mechanism.

In polar protic solvents a selenide anion (Se-2) is a stronger nucleophile as compared to a sulfide anion (S-2).

The leaving group and the departing hydrogen in an E2 elimination reaction has to be on the same side.

Halogens have lower priority as compared to alkenes in IUPAC naming system.

The rate of a SN1 reaction increases with increasing carbocation stability.

Sodium hydroxide is a strong base and can be used to deprotonate terminal alkynes in a 100% yield.

Carbocations form tight ion-pairs with halide anion.

In SN2 reactions the rate-determining step involves two molecules.

Iodine is a better leaving group than fluorine because iodine is more polarizable than fluorine. 

Vinylic carbocations can undergo carbocation rearrangement.