Problem: When methyl alcohol is treated with NaH, the product is HC 3O-Na+  (and H2) and not Na+ -CH2OH (and H2). Explain why this is so.

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When methyl alcohol is treated with NaH, the product is HC 3O-Na+  (and H2) and not Na+ -CH2OH (and H2). Explain why this is so.

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Our data indicates that this problem or a close variation was asked in Organic Chemistry - Solomons 10th Edition. You can also practice Organic Chemistry - Solomons 10th Edition practice problems.