Identify the more stable stereoisomer in each of the following pairs, and give the reason for your choice:
So, now let's go ahead and figure out which one of these is going to be more stable by using our chair confirmations, right? So let's just go ahead and draw our chairs and let's go ahead and call this one and then this will be our one position, so this is going to be over here, then our three position is on the wedge as well, so it's also going to be axial then our four position is on the dash so that means is going to be going down here, right? Already that's looking pretty good it because we know that we can get a chair flip and have all of those being in the equatorial position, here we can go ahead and say that we've got this one here, right? And then our number three is going to be in the equatorial and our number four is going to be up also in the equatorial, so this is a stable as we can get, right? We've got only two in the equatorial on one in the axial, the other way would be one in the equatorial and two in the axial, this one we can go ahead and put them all into the equatorial, so this one is going to be our more stable version. Alright guys, let me know if you have any questions, if not, let's move on.