Determine whether the two structures in each of the following pairs represent constitutional isomers, different conformations of the same compound, or stereoisomers that cannot be interconverted by rotation about single bonds.
So, here we've got two different compounds and one of them has is weird kind of boat shape, the other one has a standard bond line zigzag, right? What we're used to, but since we know that they're both in bond line we can just go ahead and count our carbons, right? So, 1, 2, 3, 4, 5, 6 fine 1, 2, 3, 4, 5, 6, so they both got six carbons and then only have the exact same number of hydrogens because of their IHD, right? they're IHD because they got no PI bonds and no rings is equal to zero, so they should both have 14 hydrogens if they got six carbons, so these are the actually, with the exact same molecular formula, they're just rotated, right? This is just rotated about an axis, so we're going to have a different conformation, okay? So, let's move on.