Organic Chemistry / Newman Projections to Bondline Structures
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Solution: Give the IUPAC names of each of the following alkanes.  ...


Give the IUPAC names of each of the following alkanes. 

Video Transcript

Okay, so here we're going to go ahead and name this compound here with IUPAC nomenclature and personally I found that the easiest way to name a Newman projection is to actually go ahead and draw it out in bond line, so we know that this is our front carbon and we know this is our back carbon, right? So let's just go ahead and draw two carbons and say we've got from our eyeballs perspective, right? We're looking down this bond, so this is our front and this is our back, I'm going to go ahead and make it pretty, right? We've got some eyelashes, I'm going to be looking down in this direction. So, from here on the front carbon all we got our hydrogens, right? So I'm not going to go ahead and draw them since we know the draw explicitly, let me shift this over a little bit, there we go, okay? So, here on the back carbon we know that we've got 3-methyl groups one is going to go ahead and be in plane and then I'm going to go ahead and draw the other ones on wedge and dash. Now, if we were talking about chirality that wouldn't really matter, right? Because we know that we need three we need four unique groups to have a chiral Center and that's usually where wedge and dash information is most important, so guys, what can we do here? first of all what's our longest change because we need to identify our root name? Well, if we go ahead and identify our longest chain we can say that any one of these methyls will give us our longest chain, I'm just going to go ahead and use them in the ones that are in plane, okay? So we can also go ahead and destroy this like this, right? That works out too and just in case we want to wedge and dash to make a little bit more clear, we can say that one of our methyls is attached there, the other one is there and we can say that we've got 2 methyls, right? on our propane because we've got our longest chain which is 1, 2, 3 carbons, so this is going to be propane and how many methyl groups do we have? like I just said, we've got two, right? one and two, so we can say that this is methyl with no space but it's dimethyl because we've got two and that would be to specify your location, no matter where we count from we get our 2 methyls coming off from our number two carbon, right? We can take this number 1, 2 and 3, so we get 2, 2-dimethyl propane as our full IUPAC name. Alright guys, let me know if you have any questions, if not let's move on.