Assuming that the rate-determining step in the reaction of 2-methyl-2-butanol with hydrogen chloride to give 2-chloro-2-methylbutane is unimolecular, write an equation for this step. Use curved arrows to show the flow of electrons.
Hey everyone in this question we're looking at our compound and the reaction that took place from our 2-methyl 2-butanol and we're looking at it reacting with HCl to go with a 2-chloro 2-methyl butane. Now, the rate determining step it tells us in a uni molecular one and it should make sense to us because we have a tertiary alcohol reacting here, so we're going to have a step that's involved where our alcohol becomes protonated, so we're going to get a compound that looks like this where we have our methyl still there but now we have a water, okay? In the reaction that it wants us to draw is our water breaking off to form a carbocation, so what that's going to look like is something like this where it looks like we can't even see our oxygen, so let's redraw it, there it is with a positive charge, we know that we're going to turn our alcohol into a good leaving group for this problem, which is a water and that's going to break off on its own, what's going to happen next is from there we're going to get a carbocation. So, here's our methyl group again, here is our tertiary carbocation, okay? From there what's going to happen is our Cl minus is going to come in and simply attack and notice how we're going to get to our final product, so this is the rate determining step for this unimolecular reaction and is going to proceed through an SN1 type mechanism, alright? so I hope this made sense and let me know if you guys have any questions.