Video Solution: Write structural formulas for all the constitutional isomers...

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Write structural formulas for all the constitutional isomers of molecular formula C3H6O that contain

(a) only single bonds

Video Transcript

So now here we got C3H6O, so we can go ahead and calculate our ihd, right? But we're going to go ahead and separate this by just drawing compounds with a single bond and then only with double bonds, okay? So we've got 2n plus 2 minus H and we know here that H's are equal to one and oxygen's are equal to 0, right? So we are just and count them, so now this is all divided by 2, right? And then we come in and we say we've got, I'm going to go ahead and just simplify this, right? We know that we've got three carbons here, so that's 2 times 3 is 6 plus 2, that's going to give us 8 minus 6 here. So, 2 divided by 2 that's going to give us an I HD of 1, which means that we've got a ring, right? Since we're only allowed to have single bonds, so we can say is we've got a triple bond, a cyclopropane like this and then we can go ahead and kick off our OH up there, can we do anything else? absolutely we can go ahead and give ourselves a cyclic ether, right? With a four membered ring, can we do anything else? sure, we can do a three membered ring that looks like this with our ol here or other carbon there bonded, and then we just have a methyl group coming off, nothing wrong with that, that works out perfectly, can we do anything else? no, actually we can't, so now let's go ahead and focus on our double bonds, so we can say that we've got our 3 carbons like that and we have our OH coming off and we can add our double bond there, we can also do this, to put our double bond over here and our OH over here, can we do anything else? sure, right? We have a cyclic ether over here, but let's just add a regular ether, so we have an O there, two carbons there, double bond there and then we've got this guy right here, right? So, there we go, can we do anything else? Not really, if we just follow this kind of path where we don't actually double bond to our O, right? We can do something like this, double bond O, that's perfectly fine and we can also do something like this, double bond O, right? Those all work, is there anything else that we can do? No, right? this is all we can do, we have eight structures here total 1, 2, 3, 4, 5, 6, 7, 8, okay guys? if you have any questions please feel free to let me know, if not, let's move on.

How many constitutional isomers are there with molecular formula C 3H6Br2?

A. 1

B. 2

C. 3

D. 4

E. 5

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True or False: The following 2 compounds are constitutional isomers of each other.

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Draw a constitutional isomer of the compound given below

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How many constitutional isomers having molecular formula  C7H16 contain  at least (1) quaternary (4°) carbon atom within the structure of the molecule?

A. 0 

B. 1

C. 2

D. 3

E. 4

F. 5

G. 6

H. 7

I. 8

J. 9

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How many constitutional isomers having molecular formula   C7H16 contain  exactly two (2)  primary (1°) carbon atoms within the structure of the molecule?

A. 0 

B. 1

C. 2

D. 3

E. 4

F. 5

G. 6

H. 7

I. 8

J. 9

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Which one of the following compound(s) is constitutional isomers of spiro[2.2]pentane?

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Draw structural formulas for 5 (and only 5) constitutional isomers that  have one (and only one) ring and that one ring must be a three-membered ring and the molecular formula C5H7F. Your structural formulas must have no nonzero formal charges and the most typical arrangements of bonding and nonbonding valence electrons. Note that if you give the same isomer more than once, points will be deducted for that isomer. If you give more than 5 constitutional isomers, points will be deducted. For this problem, you must give complete structural formulas showing all atoms and bonding valence electrons. Do not give condensed structural formulas or bond-line formulas.

 

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Choose the compound pair that are not constitutional isomers:

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Draw structural formulas for 5 constitutional isomers that have one (and only one) three-membered ring and the molecular formula C6H12. Yes, each of the constitutional isomers that you give must be a substituted cyclopropane. Your structural formulas must have no nonzero formal charges and the most typical arrangements of bonding and nonbonding valence electrons.

Note: For this problem, you must give complete structural formulas showing all atoms and bonding valence electrons. Do not give condensed structural formulas or bond-line formulas. 

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