Write structural formulas for all the constitutional isomers of
For this next one we've got C3H6, so guys I can tell you right now we have an IHD of 1, so we've got 2 times 3 plus 2 minus 6 divided by 2, that's going to be 2 divided by 2, equal to 1, right? So we're going to get is either a PI bond or a ring, so we can have something like this or we can have something like that, right? Perfectly fine, can we do anything else? No, that's all we can do, so this one would have a structural formula of CH3, CH, right? and then CH2 but normally what we do is we explicitly list that we have a double bond here, okay? Now, for this ring we have to go ahead and say we've got our CH2 over here, forgot my carbon, CH2 over here, CH2 up here, CH2 down here and then connect these two, those work out perfectly, let me know if you guys have any questions, if not, let's move on.