Write structural formulas for all the constitutional isomers of

(a) C_{3}H_{8}

So let's go ahead and come up with all the constitutional isomers for C3H8, guys we can just go ahead and use our ihd but I'm going to go ahead and just draw this one time in full and then from here on I'm just, from after this problem just going to go ahead and solve it without drawing this, without writing out the whole thing, so this is C3H8, that's 2 times n, so that 2 times 3 plus 2 minus 8 all divided by 2, so that's 0 ihd, no double bonds or rings, so we get is just this, right? That's all we can do, so we can say CH3, CH2, CH3, alright? So, let's move on.

Using line-angle ONLY, draw all isomers of C_{7}H_{16 }where the longest chain is FIVE carbons long or less.

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Draw the constitutional isomers of molecular formula C_{4}H_{9}Br. Draw the enantiomers for any that contain chiral centers.

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How many constitutional isomers having molecular formula **C _{7}H_{16}** contain the root and suffix “pentane” within the correct IUPAC name of the molecule?

A. 0

B. 1

C. 2

D. 3

E. 4

F. 5

G. 6

H. 7

I. 8

J. 9

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Draw structural formulas and give names for all of the isomers with the formula C_{4}H_{8} (Hint: There are five isomers).

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Draw the line-angle (bond-line) structure of two isomers of the following molecular formula. C_{3}H_{8}O.

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