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Solution: Name each of the following compounds according to substituti...


Name each of the following compounds according to substitutive IUPAC nomenclature: 

Video Transcript

Hey everyone. So, in this problem we were given a structural formula and we need to give that IUPAC name that corresponds to it, so what we could do is we can convert this to bond line and not show all of the atoms, so we can have the line like this, we can have a chloro you can have a bromo. Now on the other side we can have chloro and chloro, alright? So, here what we're going to do is we need to somehow number this, so we can either go this route in green or the route in red, so, which one do you think? Well, notice that there's only one bromine atom, right? And if we think of all of the substituents that we have, we have bromo, a bromine atom and chloro for a chlorine atom, so which one's going to come first in our name. Remember, we go in ABC order. So, our b is going to be out the C. So, because we're going to get 1 and 2 as our numbering systems with substituents, we want the bromine atom to actually have the number of one, okay? So, let's just compare both of the names that you guys probably came up with. Now, we can have one that's 1-bromo, okay? Now, here's where it gets a little bit interesting. So, here we're going to have -1,2,2-trichloro because there's three chlorines we need to name them all together and is ethane because we only have two carbons, the green route what we would get is now we have 2-bromo, right? And then what we have next? we have 1,1 and hopefully my 2's you can understand up there, this is going to be a 2, this is going to be a 2 and a 1 and this is now going to be 1,1 and 2, let's do our two like that and again it will be trichloro ethane but we don't want to have this one because we want our first priority groups to have come in first in alphabetical order, so that's why we do 1-bromo. Alright, so the systematic name that IUPAC name for our compound will actually be 1-bromo 1,2,2-trichloroethane, okay? So I hope this makes sense, let me know if you have any questions.