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Solution: Write structural formulas for each of the following alcohols...

Question

Write structural formulas for each of the following alcohols and alkyl halides: 

(g) 1-Cyclopropylethanol 

Video Transcript

Alright guys, so it's our job to draw the structural formula for our 1-cyclopropyl ethanol, so what is a regular ethanol look like? well, ethanol is going to be CH2, CH3, OH or you can represent it like this, okay this is your ethanol, just regular ethanol. But now we have cyclopropyl. Now, on its own you should record you should know that a cyclopropane is just this, this equals cyclopropane, right? Just a three carbon ring, so essentially what we're doing just combining two but we know that our ethanol at position 1, we have our alcohol but also at position one where I have this cyclopropyl group, it's going to be a substituent, so we can represent this by showing that we have an OH, a CH2, CH3 and also this cyclopropyl group, let's draw that a little bit bigger, so we have this three membered ring, so this is what your one cyclopropyl ethanol would look like. Now, let's say we converted this into an a structural formula where we show all of the atoms in our molecule. So, in the beginning in this Center we had a carbon that has one hydrogen on it, we know that we can also show that we have an OH group, so that OH is going to be right there. Now, on one side we can show that we have a CH3, okay? and on the other reaction,we have a three membered ring then we keep the ring as it is, okay? So now this would be a representation of your structural formula, we show that there is a hydrogen coming off of right here, and I'm going to, let's do that in a different color, so in blue, there's the hydrogen here, this is going to be a CH3 and then we have our three membered ring of course. Alright, so that's showing you where all of our atoms came from in our structural formula and it's helpful to draw first the formula that doesn't show the atoms and then convert it into one that does but the trickiest part of this question was to recognize that cyclopropyl was actually a three membered ring as a substituent and then coming off of one we had an alcohol as well. Alright, so I hope this makes sense and let me know if you have any questions.

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