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Solution: Using the method outlined in Section 2.13, give an IUPAC nam...

Question

Using the method outlined in Section 2.13, give an IUPAC name for each of the following alkyl groups, and classify each one as primary, secondary, or tertiary:

 

Video Transcript

Alright everyone. So, for this question we're going to be giving this alkyl group a IUPAC name and determining, if it's going to be primary, secondary or tertiary, so let's actually start with the IUPAC name. Now, notice that this group here, let's highlight it a little bit darker because I want it to stand out to you, this is the point of attachment, okay? Because this an alkyl group. So, looking at this carbon now, this is going to be the first carbon that's the point of attachment. So, in order to give this an IUPAC name we need to actually start numbering right here, so this would be one, we move in this direction, this is two. Now, we should start going around the ring three, four, five, six, seven, eight, what do you think? Well, is that a straight chain? No, right? is a ring. So, actually how we're going to number this is we just leave it at two carbons, right? this is our longest straight chain and everything else what you see is a substituent, so this group right here is a cyclohexane ring, so this is going to become a cyclo hexyl group and then we have two carbons in there and that's actually going to be our root, it's not going to be a cyclo hexyl ethane or anything like that, it's actually going to be named as an alkyl group, so it's going to become cyclohexyl ethyl and to make this more accurate what we need to indicate is the position of our substituents. So, where is that ring coming off, is it coming off of carbon 1 or carbon 2, it's coming off of our carbon 2, so this is going to become 2-cyclo hexyl ethyl, okay? It sounds a little weird but this is what it's named as an alkyl group, okay? So now I left the easiest part for us, it's to determine if the carbon or if this alkyl group is primary, secondary or tertiary and I've highlighted that point of origin in the beginning because we're going to be using that to identify if it's primary, secondary, tertiary, so the highlighted carbon all we need to do is say at that point of attachment how many other carbons is that connected to, and very easily you would say it's just connected to this one carbon and that's how easy this into becomes, it is a primary alkyl substituent, okay? For a primary alkyl group alright? So, this is a systematic name the two cyclohexyl ethyl and in it a primary alkyl group.

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