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Solution: Write a structural formula for each of the following compoun...

Question

Write a structural formula for each of the following compounds:

 (c) 4-Isobutyl-1,1-dimethylcyclohexane

Video Transcript

Hey everyone, so the compound that we need to draw a structural formula for is 4 isobutyl 1,1 dimethylcyclohexane, so we're going to take this, we're going to break it down into three different parts, we're going to say that one of the parts where you break it down to is this dimethyl, or excuse me, just a cyclohexane, that's going to be one part and other parts going to be that's 1,1 dimethyl, right? we need to add those methyl groups at position 1 and then relative to that position in position 4 we're going to add on isobutyl group. So, cyclohexane. Notice that if there's no double bonds and it's six carbons means it's hex and then cyclo indicates that we have a ring, so that started out hopefully all of you got this form, right? We have a six membered ring. Now, this is your cyclohexane but we need to make it 4-isobutyl 1,1-dimethyl, right? So let's say we pick position one, we can pick whatever we want, let's say we take right here at the top. Dimethyl indicates that we're going to have two methyls coming off of that position one, so if that's position one, we can go to the left or to the right and start numbering either way, we get to position 4 right there, and now what substituent are we drawing at position 4, Well, it's isobutyl, so there's different groups, we have tert butyl that looks something like that, we can have just a regular isopropyl group, it's going to look something like that but the one we have is isobutyl. So, in order to draw that we're going to draw an iso group like that and this is going to be our isobutyl group, okay? So let's draw that group in at position 4, we have that one carbon and that's it, this is going to be your isobutyl group. So, take a look guys, we just drew the correct structural formula for, 4-isobutyl, right? at position 4 is that group 1,1-dimethyl, we saw, we had our two methyl groups and the cyclohexane ring, okay? So, let me know if you got any questions.

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