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Solution: Give the IUPAC name for each of the following compounds: ...

Question

Give the IUPAC name for each of the following compounds:

Video Transcript

Hey everyone, so this problem is our job to give this bond line structure and IUPAC name, so this one's actually a little bit tricky and let's see why, so the first thing that we do is you always start numbering, right? So we get started, I'm going from the left or the right, hopefully how you guys are thinking to start number right here, okay? So let's say we number from here, we have 1, 2, 3, 4, 5, 6, 7 and 8, wait a second, we can also have 7 and 8 but they will be the same thing, they're both ethyl groups, let's keep that like that but now we can also label this as 1, 2 same thing up here, 1 and 2 then we have 3, 4, 5, 6, 7 and 8. So, both of these appear to be an octane, right? No one would disagree with that, but wait a second, how do you know which one to do? Well, we always know to give our substituent with the lower number, right? So it looks like our substituent comes up at 3 in the red and it comes up in 3 and the green. So, how do we figure out which one's the correct way to start numbering? Well, this trick you may have not needed to know by now but if we have 3 ethyl and we have 3 methyl, what do we usually do? we always want to carry our IUPAC name in alphabetical order. So, actually the 3 methyl will win here, okay? So we're going to go the route that give our ethyl group the number 3, so that would be our green route, okay? So we're going to stay with our three route here, erase our route in red and we can also erase this right here. So, now that we have our substituents we also have ones that we didn't get to at 4, 5 and 6 but all of those are methyl groups, so that will become is at 4,5,6, we're going to get a trimethyl, which we know because of this m group, not the t, is going to come second, so let's start putting this together, seems like we have all of our pieces, we have first 3-ethyl, right? And just, so you guys know that's the substituent, right? So then we have methyl, methyl and methyl and then after our 3-ethyl, we're going to do another two and then we get our 4, 5 and 6 and I didn't mention this but also we didn't go the red route because, take a look, our constituents if we did that will also be at 4, 3, 4, 5, and 6, okay? So, not only that ethyl comes off of the methyl but the other substituents come in an order that none beats the other, so we have to resort to it being between the first substituent ethyl and methyl but if it wasn't ordered the way it was and our constituents were in such a way that we got the same numbers then you would go to route that ate our lower number to the lower substituents, okay? So it doesn't become 4,5,6 tri-methyl and then finally the last thing is octane, okay? Because there's eight carbons long, okay? So, again let's repeat the name that's 3-ethyl 4,5,6-trimethyl octane. Alright, so I hope this makes sense, let me know if you had any questions.

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