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Solution: Give the IUPAC name for each of the following compounds: (b...

Question

Give the IUPAC name for each of the following compounds:

(b) (CH3)2CHCH2(CH2)14CH3

Video Transcript

Hey everyone, so they give us this structure here, this formula, and they want us to give the IUPAC name for it, so notice that we have the big 14 in there, so what I'm actually going to do is I'm going to draw this out for you, so you can actually see what this looks like. Notice that a the end we have CH3 to the two, right? We have two of those and we can continue with a 14 carbon long alkane chain. Now, I'm just going to want to account this, we have 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 should be 11 and it's going to be 18 in total and actually how I got that this is 12, 13, 14, 15, 16, 17 and 18, we have 12, 13, 14, 15, 16, 17 and 18, so this is how I got that. Notice that at the end we have CH3, so this CH3 corresponds to this one right here, right? At carbon 18 then we have in a row 14 CH2 groups and let's highlight that in blue. So, 14 CH2 groups, right? So let's go ahead, we have 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, right? Coming up with that we also have another CH2, which you see here and then a CH group, okay? So that's how we got to our 18 carbons because then at the end we have two methyls, right? So we have these two groups right here correspond to this and that's what about CH groups. So, now what we need to do is name this thing, right? So, what you'll notice is that if I take this structure, copy and I'll work with it up here, I'm just going to erase all these colorings, right? So that doesn't distract us, let's get rid of all this, I know some of the numbers are still there but I want you to realize this, we're going to number this from giving our only substituents the lowest number at carbon 2, okay? it will be incorrect you start from the right and go to the left. Now, when you're naming carbons alkane chains that are 10 to 19 carbons long what you should remember is that you're all going to have the root of decane but based on how many carbons it is in between there, again we're going to use that views or 10 right here it's going to be octa because it's 18, so we would say it's an octa decane, we're still need to name our constituent, so what this becomes is at 2 we have a methyl group and we're going is at 2 methyl and then we're going to take this off the decane and bring it down here and now this whole name is going to be 2-methyl octa decane, so remember when you're naming 10 to 19 carbon you're always going to have decane in your name, okay? And as an octa comes from this being 18 carbons, okay? So the actual IUPAC name for the structure is going to be 2 methyl octa decane. Alright, so I hope that makes sense, let me know if you have any questions.

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