For each pair of compounds below, determine whether they are identical compounds, constitutional isomers, stereoisomers, or different conformations of the same compound:
Hey everyone. So, here we have these two chairs confirmations and they're both six membered rings, right? Just written as their chair form and notice that they both have two substituents on them as well. Now, the substituent that they have is simply a CH3 group, right? this is just a methyl and again over here a methyl. Now, before you guys think about, are these facing the same direction? are they cis, are the trans? there's actually an easier way to look at these two compounds and determine their relationship. Now, yes you can notice that they're both facing up in both compounds but even more, did you guys realize their connectivity? Now, say we try to identify the number the carbons that these substituents come off of and we try the number them,, we say that over here we have a carbon one, over here we have a carbon one. Now, where is our next substituent? it's not at carbon two, it's actually requirement three, so the relationship of our substituents is 1,3. Now, over here. Notice that take a look at carbon 2 we have our methyl. So, here's their relationship is 1,2. Now, if, what is 1,3 dimethyl and the other one's 1,2 dimethyl are they connected the same? No, right? one's that carbon 2 and ones at carbon three but do they have the same molecular formula? yeah, they do. So, what that means that these are constitutional isomers of each other because remember the definition of constitutional isomers is that two compounds have the same molecular formula but they only differ in their connectivity, which is exactly the case here. So, we should be able to say that these two compounds are actually constitutional isomers of each other, they're actually not identical and they're not two totally separate compounds, they actually have a relationship. Alright, so hopefully this made sense that these two compounds are constitutional isomers if you have any questions just go ahead and let me know.