What is the systematic name for each of the following compounds:
Alright guys, let's get started by naming this compound. Notice that this is not going to be just a regular systematic name. Remember, when we talked about those bicyclo, this is going to be the one that's actually a fuse and bridge bicyclo, right? So, here. Remember, that we need to indicate in parentheses the number of rings we have and the number of carbons in those rings. Remember, this is going to follow that pattern where we have a byciclo. Remember, this would be a zero if this was just fused, right? But here we actually have these two bridgeheads or excuse me these two bridge carbons. So, in our bridge there's two carbons which means that this number is not going to be a zero, right? What it's actually going to be is a two, okay? And then what we need to always remember, is that, when naming these, we want to start at these bridgehead carbons, we want to always give these carbons right here in number one and then go to the larger ring. So, here we would expect this to be number of carbons in our larger ring but here notice that both of our rings only have two carbons in them, so we go 2, 2, 2. So it's going to represent the root of this. Now, let's erase, let's just keep those numbers there. Now, remember we're starting numbering at this one. Now, we want to go to the larger ring, both of our rings are the same size, we should expect to just be at two, three and four, right? And notice that we just found our substituents there at 1 and 4, but the count the number of carbons because remember this is going to just be alkane at the end, we need to continue along, so that's going to be 4, this is going to be 5, 6 then up here is going to be 7 and 8, so we're going to say that this has an 8 carbon chain. So, our octane here is actually going to be, our alkane, excuse me, is going to be an octane. Now, we're almost done, right? Hopefully all that made sense, we're starting at our bridgehead carbons and giving them a number 1 going to the larger ring, here they're both two carbons, right? So we're fine. And now all we need to do is label the substituents as methyl groups, okay? So, our substituents are just at 1 and 4. So, 1, we have a methyl and at 4 we have a methyl, so this is going to start out being 1, 4 dimethyl and then, what do you think is going to happen after that? you guys got it, we're going to label include this thing right here, so let's start at the bottom, like we mentioned it's going to be a 1, 4 dimethyl, right? Because that's our substituents, meaning it starting at the bridgehead and then from there we just include that we know that this is a byciclo 2, 2, 2 octane, okay? So this is how we arrived at our name. Now, there's different things to worry about here when we have two rings that are different size or substituents that are symmetrical like this, there's one at one there's one at 4, if say there's a substituent at two also then we would, we must go this route but here we could have totally gone and counted this our 2, this is our 3 and this is our 4 as well. Alright guys but our name here is just 1, 4 dimethyl bicyclo 2, 2, 2 octane. Alright guys, so let me know if you have any questions that I hope this made sense.