Each of the structures in the previous problem has one or more substituents connected to the parent.
(d) Identify the common name and the IUPAC name of the complex substituent in 4.39d.
Alright guys. So, for this question to start out, let's first find the parent chain, so that we can identify what our substituents are. Now, hopefully you guys realize that our parent chain is going to be this one at the bottom, it's the longest straight chain here, right? So this is our parent, that's going to give us our route but everything else here that's not highlighted is going to be a substituent and they have names, so notice that our substituent here is going to be this group, right? this is going to be our substituent. Now, how many carbons do you see in it I count four, right? So we can actually name this two different ways, there's a common name that you'll see, for this one it's called tert butyl. okay this is a tertiary butyl group or commonly called terbutyl, right? or there's another name that IUPAC sometimes likes to use. Now, for that one, we actually need to name it like it's its own kind of chain, what I mean by that is, let's say, we call this one and then one of these two, that's going to be the longest chain, right? Two different carbons. Now, we can also call everything off of one a substituent, right? So, this going to be a substituent, we can say substituent A, and this can be a substituent as well substituent B. So, here notice that it's going to be it's getting a different color, is going to be some kind of ethyl, right? Because it's two carbons long, let's write that over here, right? We know it's going to be some kind of ethyl but now we need to name our substituents, so we can call this a 1,1 dimethyl, right? Ethyl group, okay? So, commonly its called terbutyl but we can also call it a 1,1 dimethyl, right? there's a methyl at A and B, ethyl because it's 2 carbons long. So, common again was tertbutyl and then there's an other name that IUPAC likes to use as well, so hopefully this made sense guys and let me know if you have any questions.