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What is the molecular formula for each compound in the previous problem?

Hey guys, let's take a look at our compound here. Notice that we have three carbons there, this is our four, five, six and then there's an alcohol group. So, in total we say we have 1, 2, 3, 4, 5, 6, right? or no, we could do it the other way, we could start here at our alcohol 1, 2, 3, 4, 5 and 6. So, six carbons in total all we're looking for is a molecular formula. So, again C6H something and then we're going to have one O like this. Now, all the hydrogens are going to be grouped together. So, all we need to do is count how many hydrogens we have. So, note here we're going to have three, here we're going to have three, so that's six so far, here's going to be a hydrogen, that's seven, eight, nine, ten and eleven, twelve and thirteen and then don't forget about this hydrogen. So, how many hydrogen's that we just count? there is 14, okay guys? So, what this is is a regular alkane, so we should expect that our C6H14 is a formula for regular alkane such as CNH to the 2n plus 2. Now, that would give us 14. Now, all that's different here is we have an extra oxygen, so that's indicated in our formula as well, so this all makes sense, right? So, C6H14 oh is the molecular formula for our compound. Alright guys, so hopefully that made sense and let me know if you have any questions.