What is the molecular formula for each compound in the previous problem?
Alright guys, so for this question is looking for the molecular formula, so let's first take a look at our structure. So there's three metals here, then we have carbon 4, 5, 6, 7, 8 and 9, okay? So let's count our carbons a little quick, we have 1, 2, 3, 4, 5, 6, 7, 8 and 9, okay? Let's just move this 8 over a little; we have in total 9 different carbons on the structure, okay? And notice that, let's just draw it in one more time, notice that it's just a regular alkane, right? No double or triple bonds involved, so we counted that there's nine carbons. Do you remember how we can predict how many hydrogens have in a regular alkane? There's a formula, or the other method would just be to count over hydrogens but that could be a little tedious especially in a bigger molecule. Well, the formula, remember for a regular alkane is going to be C to the n, right? We have nine carbons, so n equals 9 and then H to the 2n plus 2. So, if we do 9 times 2 you get 18, and then we have to add in 2 more hydrogens for our formula, so we should expect to get C 9, H how much? not 18, right? It's going to be 20. And if you want you can actually go ahead and check that you'll find 20 different hydrogens here on our structure. So, our molecular formula for this regular alkane thatÕs nine carbons our total is C 9 H20. Alright, guys, so I hope that made sense.