Write an equation for the proton transfer reaction that occurs when each of the following bases reacts with water. In each case, draw curved arrows that show the mechanism of the proton transfer:
Okay guys, so let's go ahead and figure out what happens here, when we have our benzene with a negative charge, so we can just think about this as an alkene, right? Because we've got double bonds throughout this molecule and the negative charge is located where there's double bond, right? So guys we also are reacting this with water, so let's go ahead and compare of pka's, what's the pKa of water? pka of water is 15.7, how about an alkene? we know it's 44. So guys, this is also a huge difference. So, do you expect to find an equilibrium arrow? probably not, right? if you expect to find something almost completely forward reaction, okay? So what's going to happen here? our negative charge is going to come in, our lone pair is going to come and attack this hydrogen, which I'll draw it explicitly and then what's going to happen is that these electrons are going to jump on to that O, right? they're going to be pushed onto that oxygen and then we, what we end up with is our benzene here where we have all of our hydrogen drawn implicitly and then we also have our hydroxide. Alright guys not so bad, right? Let's move on.