For diisopropyl ether in mass spec analysis, O will lose 1 lone pair which will give us the molecular ion as:
The mass spectrum of diisopropyl ether is shown below:
1. Draw the radical cation giving the molecular ion. Be sure to include the nonbonding electrons on the oxygen.
2. Identify the fragment giving rise to the peak at m/z = 87. Be sure to include the nonbonding electrons on the oxygen.
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