For C_{6}H_{13}N:

(1) Calculate for the IHD:

$\overline{){\mathbf{IHD}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{(}\mathbf{2}\mathbf{n}\mathbf{+}\mathbf{2}\mathbf{)}\mathbf{-}\mathbf{H}}{\mathbf{2}}}\phantom{\rule{0ex}{0ex}}\mathbf{IHD}\mathbf{}\mathbf{=}\mathbf{}\frac{\mathbf{(}\mathbf{2}\mathbf{\left(}\mathbf{6}\mathbf{\right)}\mathbf{+}\mathbf{2}\mathbf{)}\mathbf{-}\mathbf{12}}{\mathbf{2}}$

IHD = 1

where H or X = 1; N = -1 and O = 0

Structure is either cyclic or has 1 double bond

(2) Inspecting the signals for IR:

3280 cm^{-1 }→ likely an amine

1653 cm^{-1} → possibly imine or amine

Provide a structure for the following compound:

C_{6}H_{13}N;

IR: 3280, 1653, 898 cm^{-1};

^{1}H NMR spectrum;

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