Draw bond-line structures for all constitutional isomers of C 4H10.
Alright guys. So, for this question we want to draw the constitutional isomers before our C4H10, okay? So remember that constitutional isomers have the same molecular formula but they're just connected differently, okay? So the first one I can think of is just a straight chain like this, where notice that this is going to be C4H10 because we have four carbons and of course we have three hydrogens here to there, to there and 3 there, okay? So remember that these are all hydrogens, in total we'll have 10. Now, we need to can actually connect these four carbons in a different orientation, so let's say we drew that same chain again, let's say we erased this one, so this is where it originally was, okay? Now, let's say we tried to actually draw it in over here, okay? Now, notice that if we're just looking to add this right here, right? Notice that it would be the same exact compound as before, so we can't include it there but let's say we actually included it here, okay? And we just look at this. Notice we have our 1, 2, 3 and our 4, is right there, and take a look, we have three hydrogens, we have, I'm going to erase this right now, we have three hydrogens here, we have one there and then three right there, so let's actually draw both of these and again, just recap, we have two different ways to draw a constitutional isomers, okay? two different constitutional isomers are for our C4H10 these are the only two would work, we cannot have anything like this or like that because these won't have the right number of hydrogens, both of these will be equal to C4H8. Alright guys, so these are your two answers and hopefully that makes sense.