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Solution: Identify the hybridization state and geometry of each carbon...

Question

Identify the hybridization state and geometry of each carbon atom in the following compounds: 

Video Transcript

Hey guys, so let's go ahead and figure out our hybridization and our geometry for this molecule, okay? So, well for the carbons in this molecule, so what I'm going to do is label them with colors and then we're going to figure out what they are. Okay, so what's our yellow carbon? our yellow carbon how many groups does it have? it's got four groups, right? Because we're hydrogens are implied, we've got our three hydrogens over here and our group over here, the propyl group, right? So, what we expect to find is an sp3 hybridized carbon that is going to be tetrahedral, right? What about the propyl one? the propyl one guys, how many groups does it have? it's got three, right? The oxygen and the yellow and green carbons, so it's actually going to be an sp2 hybridized carbon, which means it's going to have a trigonal, let me go ahead and spell it out, a trigonal planar geometry, and if you guys need help or you know more review bond line, Johnny has great videos on understanding it. Guys, what about this green one? Well, it's got this blue, this purple and these two hydrogens that are implied here, so we expect to find that it's sp3 and it's going to have a tetrahedral geometry, right? So now what about the blue? the blue is going to have its four groups, right? The three hydrogens and the one green carbon, so we expect to find an sp3 hybridized carbon with a tetrahedral geometry. Alright guys, not so bad, let's move on.

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