Identify the hybridization state and geometry of each carbon atom in the following compounds:
Hey guys, so let's go ahead and figure out the hybridization and geometry of each one of these carbons, okay? So let's go ahead and identify how many carbons we actually have, we have one here, which is exactly the same as this carbon, we have another one here, same as that carbon and we have another one here and here, right? They're exactly the same, because we have a plane of symmetry between that axis, right? in that axis, so guys remember that we have our hydrogen implied, so we do have either hydrogen here, no hydrogen here but we do have hydrogens here as well, so I'm going to go ahead and draw these explicitly, okay? So now guys, if we're looking at the yellow carbons, what are we going to get? the yellow carbons, right? We know that they're SP hybridized, right? Because they've only got two groups, one the propyl carbon and the hydrogen, right? So we expect to find is we're going to get SP and what's our geometry? linear, right? Okay, so now what about the purple? the purple is also SP hybridized, right? Because we've got this yellow carbon and this green carbon and that's it, right? So we're going to have an SP and linear, right? So now what about this green carbon? the green carbons well, how many groups that actually have? they've three, right? This propyl carbon, this hydrogen and this other green carbon, right? So we're going to get is an sp2 and what are we going to have as our geometry? we're going to have a trigonal planar geometry, right? Okay, so that one wasn't so bad, let's move on.