Problem: When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potassium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the mixture. But when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the mixture. What would you predict for the percent of 2-methyl-1-butene in the mixture if potassium propoxide were the base? a) less than 45% b) 45% c) between 45% and 70% d) more than 70%

🤓 Based on our data, we think this question is relevant for Professor Stocker's class at UMD.

FREE Expert Solution
Problem Details

When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potassium hydroxide is the base, 2-methyl-1-butene accounts for 45% of the mixture. But when potassium tert-butoxide is the base, 2-methyl-1-butene accounts for 70% of the mixture. What would you predict for the percent of 2-methyl-1-butene in the mixture if potassium propoxide were the base?

a) less than 45%

b) 45%

c) between 45% and 70%

d) more than 70%

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Rate Calculations of Competitive Mechanisms concept. If you need more Rate Calculations of Competitive Mechanisms practice, you can also practice Rate Calculations of Competitive Mechanisms practice problems.

What is the difficulty of this problem?

Our tutors rated the difficulty ofWhen 2-bromo-2-methylbutane is treated with a base, a mixtur...as medium difficulty.

How long does this problem take to solve?

Our expert Organic tutor, Chris took 4 minutes and 14 seconds to solve this problem. You can follow their steps in the video explanation above.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Stocker's class at UMD.