Ch. 19 - Aldehydes and Ketones: Nucleophilic AdditionSee all chapters
All Chapters
Ch. 1 - A Review of General Chemistry
Ch. 2 - Molecular Representations
Ch. 3 - Acids and Bases
Ch. 4 - Alkanes and Cycloalkanes
Ch. 5 - Chirality
Ch. 6 - Thermodynamics and Kinetics
Ch. 7 - Substitution Reactions
Ch. 8 - Elimination Reactions
Ch. 9 - Alkenes and Alkynes
Ch. 10 - Addition Reactions
Ch. 11 - Radical Reactions
Ch. 12 - Alcohols, Ethers, Epoxides and Thiols
Ch. 13 - Alcohols and Carbonyl Compounds
Ch. 14 - Synthetic Techniques
Ch. 15 - Analytical Techniques: IR, NMR, Mass Spect
Ch. 16 - Conjugated Systems
Ch. 17 - Aromaticity
Ch. 18 - Reactions of Aromatics: EAS and Beyond
Ch. 19 - Aldehydes and Ketones: Nucleophilic Addition
Ch. 20 - Carboxylic Acid Derivatives: NAS
Ch. 21 - Enolate Chemistry: Reactions at the Alpha-Carbon
Ch. 22 - Condensation Chemistry
Ch. 23 - Amines
Ch. 24 - Carbohydrates
Ch. 25 - Phenols
Ch. 26 - Amino Acids, Peptides, and Proteins

Imine vs Enamine

See all sections
Sections
Naming Aldehydes
Naming Ketones
Oxidizing and Reducing Agents
Oxidation of Alcohols
Ozonolysis
DIBAL
Alkyne Hydration
Nucleophilic Addition
Cyanohydrin
Organometallics on Ketones
Overview of Nucleophilic Addition of Solvents
Hydrates
Hemiacetal
Acetal
Acetal Protecting Group
Thioacetal
Imine vs Enamine
Addition of Amine Derivatives
Wolff Kishner Reduction
Acid Chloride to Ketone
Nitrile to Ketone
Wittig Reaction
Ketone and Aldehyde Synthesis Reactions
Additional Practice
Physical Properties of Ketones and Aldehydes
Multi-Functionalized Carbonyl Nomenclauture
Catalytic Reduction of Carbonyls
Tollens’s Test
Fehling’s Test 
Alkyne Hydroboration to Yield Aldehydes
Nucleophilic Addition Reactivity
Strecker Synthesis
Synthesis Involving Acetals
Reduction of Carbonyls to Alkanes
Clemmensen vs Wolff-Kischner
Baeyer-Villiger Oxidation
Baeyer-Villiger Oxidation Synthesis
Weinreb Ketone Synthesis
Wittig Retrosynthesis
Horner–Wadsworth–Emmons Reaction
Carbonyl Missing Reagent
Carbonyl Hydrolysis
Carbonyl Synthesis
Carbonyl Retrosynthesis
Reactions of Ketenes
Ketene Synthesis
Additional Guides
Acetal and Hemiacetal
Johnny Betancourt

Imines and Enamines are the products formed by the nucleophilic addition of a primary (1˚) amine, secondary (2˚) amine, or ammonia (NH3) to carbonyls such as ketones or aldehydes.


Click here to watch the full video! 

Imine vs. Enamine: What’s the difference? 

Imines look like carbonyls and are formed from a primary amine (or ammonia) reacting with some type of acid (H+, H3O+) with a carbonyl. In simplest terms, it looks like a carbonyl with a double bond to nitrogen instead of oxygen.

Imine StructureImine Structure

Notice that after the reaction is over, you will be left with a structure that looks like this (above in green). The 3 carbon chain coming off is simply the R group that was attached to the original primary amine before it reacted. 

On the other hand, enamines form from carbonyls reacting with a secondary amine and does not have a double bond to nitrogen, but instead to carbon.

You can remember this because the nitrogen already has 2 R groups in the beginning and therefore would be positively charged if it contained a double bond. For example:

Enamine StructureEnamine Structure

Notice that the double bond here is between 2 carbons: 1 from the carbonyl carbon that formed it, and the other is the alpha carbon.

Enamines are formed from the same mechanism that imines are formed except for the final step which is deprotonation of the iminium cation (more on this to come later).

The Reaction:

     A. Reagents 

Imine ReactionImine reaction

The reagents needed to form an imine are simple and really come down to 3 things:

  1. A carbonyl
  2. A primary (1˚) amine or NH3, a type of 0˚ amine
  3. And finally an acid such as H+

It is commonly seen to combine parts 2 and 3, the NH3 and the H+, so that we don’t have an extra step involved. If we did this the reaction simply looks like this:

Ammonium PreparationAmmonium Preparation

For enamines, the amine being used will be 2˚ and therefore commonly seen is a cyclic amine such as azetidine:

Secondary Cyclic AmineSecondary Cyclic Amine

Assuming protonation like we did before, we would get the reaction seen below and be ready to start our mechanism.  

Protonated AmineProtonated Amine

Now, as we go into the mechanism we will focus on forming the imine through 0˚ or 1˚ amines. However, if we use the cyclic protonated amine above, the mechanism is the same until we get to the end 

     B. Mechanism Overview

Protonation is the first step where the oxygen from the carbonyl reacts with the protonated amine that we formed above. As you can see below we have already taken a proton and formed our +OH.

From here we can draw a resonance structure so that we have a positive charge not on the oxygen anymore like before, but now on the carbon of the original carbonyl.


Resonance StructuresResonance Structures

The green resonance structure is not absolutely necessary to draw because the arrows will be exactly the same once we perform the next step, however it is a more complete picture and sometimes easier to visualize.

Next, a nucleophilic attack [1,2-addition] occurs with the lone pair from the original neutral amine to the positive charge on the carbon. From this, we get a tetrahedral intermediate with a new C-N bond and nitrogen now has a positive charge again.


Tetrahedral Intermediate Tetrahedral Intermediate 

*Note: Does this look familiar? This is a very common intermediate for nucleophilic addition reactions such as the acetal/hemiacetal mechanism.

Now, you may want to draw the NH3+ with one of its H’s hanging off to the side because we are trying to eliminate water and therefore do a proton exchange, which is our next step. This means the oxygen from the OH will grab one of the H’s from the H-NH2+ (this is simply NH3+ arranged differently) and form –H2O+.


Proton Transfer StepProton Transfer Step

Once we form water we can kick out our leaving group or eliminate water. The way we do this is to use the electrons from the nitrogen, form a double bond between carbon and nitrogen and in the process form an iminium ion. Is the product looking familiar now?


Elimination StepElimination Step

At this point we have our iminium cation which will be your checkpoint for these types of reactions. If you don’t get this structure you most likely did something wrong and should go back to your mechanism and the different steps to figure out where you want off track.

For the enamine mechanism, this will be the tetrahedral intermediate formed before we do a proton transfer and form water. From here, water will be our leaving group again that will be kicked out in our next step.


Enamine Tetrahedral Intermediate Enamine Tetrahedral Intermediate 

     C. Intermediates 

This is the general formula for the iminium cation (R2C=NR2+), which is the key intermediate for imine and enamine reactions.

Iminium Cation General StructureIminium Cation General Structure

The iminium cation formation will be our last intermediate before we get to our final product which can either be an imine or an enamine. From here we can use water or the conjugate base of our original NH4 which is NH3 (ammonia), to deprotonate the final H on the nitrogen to give us our final product, an imine.


Iminium CationIminium Cation

The iminium cation for enamines looks very similar. Below is an example of one when the amine used was secondary (2˚) and cyclic.

Iminium Cation of an EnamineIminium Cation of an Enamine

     D. Products

Imine ProductImine Product

Imine general formula: R2C=NR

The product of the imine mechanism will look like a carbonyl except there is a N (nitrogen), instead of an O (oxygen) and an extra H (hydrogen) is attached. The rest will simply be our byproducts.

Also, notice that NH4was reproduced, but if we used water to deprotonate our iminium cation we would instead have H3Oand NH3 as byproducts instead. Both would be correct!


Enamine ProductEnamine Product

For enamines our product would not have the double bond to nitrogen, but instead a double bond from the original carbonyl carbon position to one of the alpha carbons (more on this below).

Specific for Enamines: 

All the steps above were described for when a 0˚ or 1˚ amine is used, however when a 2˚ degree amine is used we get a different last step. That is because if we look at our iminium cation (in green above) we have no hydrogen to deprotonate on nitrogen.

The question we ask ourselves then would be: Where do we have a hydrogen (H) to remove from? The answer to that is at our alpha position from our original carbonyl.

Just as before, remember we can deprotonate with the conjugate base, which in this case would be the cyclic amine (seen below), or water.


Deprotonation Step for Enamines

Deprotonation Step for Enamines

Related Topics: 

     1. The alpha (α) position 

We mentioned the alpha position briefly when talking about enamines, but why is this important? Well, it turns out that enamines can do reactions at their alpha position just like many other compounds in Organic Chemistry, like enols & enolates.

The alpha position, due to its unique acidity (pka ~ 20), allows for compounds like enolates and enamines to undergo different reactions (alkylation an acylation) at the alpha carbon.

Enamines specifically are able to use their nucleophilic alpha position to add different R groups and form alpha substituted carbonyls. This happens via an iminium salt intermediate that is able to be hydrolyzed back to a carbonyl.


Enamine Alkylation & Hydrolysis Enamine Alkylation & Hydrolysis    

2. Hydrolysis 

Hydrolysis in this case is referring to the ability to go from our iminium salt back to our carbonyl using water and a little bit of acid. The mechanism involves 5 steps: protonation, addition of H2O, proton transfer, elimination, deprotonation. Seem familiar? 


Here is a video of that mechanism being used to convert an ester back to a carboxylic acid.


The hydrolysis can be done for both imines and enamines to turn them back into carbonyls, as see below with the hydrolysis of an enamine.

Enamine HydrolysisEnamine Hydrolysis

This hydrolysis mechanism will be important when doing enamine alkylation and acylation problems because hydrolysis back to the carbonyl is usually the last step.

     3. Tautomerization 

Another important topic arises when discussing enols, the alpha carbon, and ketones in particular, which is tautomers and tautomerization. The reason this is applicable is because imines and enamines can tautomerize with each other.


First, we have keto-enol tautomerization which can be acid or base catalyzed. Remember, these 2 compounds are simply constitutional isomers.


Keto-Enol TautomerizationKeto-Enol Tautomerization

The same rule applies with imines and enamines. Notice the only difference between the 2 is the double bond and 1 H (hydrogen) switched places.

Imine Enamine TautomerizationImine Enamine Tautomerization

This concept of tautomerization with imines and enamines will become increasingly important when dealing with synthesis reactions where you need to add R groups to the alpha position.


     4. Schiff bases & other nitrogen compounds 

Now, when we say imines we should recognize that they can also be referred to as Schiff bases when the group attached to the N is not hydrogen, but an alkyl group.

Take for example the structure below, which is the general structure for an imine.

Imine General StructureImine General Structure

We can actually call this compound different names based on what R1, R2 and R3 is. Let’s go through some of the most common names:

  • If R3 ≠ H it is termed Schiff base
  • If R3 = H and R1 or R2 = H it is termed primary aldimine meaning the imine was derived from an aldehyde
  • If R3 ≠ H and R1 or R2 = H it is termed secondary aldimine
  • If R3 = H and R1 and R2 ≠ H it is termed primary ketimine meaning the imine was derived from a ketone
  • If R3 ≠ H and R1 and R2 ≠ H it is termed secondary ketimine

Some other names you may come across are aziridine, hemiaminals, azides, and a nitroso compound.

  • Hemiaminals are simply the first intermediate we see in the imine mechanism where a central carbon is attached to a hydroxyl (OH) an amine (NR2), and 2 R groups.
  • Nitroso compounds are those that contain a “­–N=O” group where the N (nitrogen) is attached to an R group such as carbon, nitrogen and even sometimes oxygen.
  • Aziridine refers to a structure with the chemical formula C2H5N. It is basically a 3 membered ring with a NH group attached to 2 CH2’s. It can also be seen named as ethylene imine.
  • Finally, azides are simply N3- or sometimes referred to as the azide ion. You may have seen this structure back when you learned about formal charges. Structure wise it can be represented 3 different ways if we include resonance structures.


     5. Aldol condensation

Lastly, just be aware that enolates, which react very similar to enamines, can undergo a condensation reaction known as aldol condensation. It is when 1 enolate acts as a nucleophile (Nu-) and attacks an electrophile (E+) such as another carbonyl.

This forms what is known as a ß-hydroxycarbonyl which can dehydrate via 2 mechanisms to form a conjugated unsaturated carbonyl.

Here is an example: (more details on this later)


Aldol Condensation MechanismAldol Condensation Mechanism

Q and A: 

Why is it necessary to draw equilibrium or reversible arrows?

  • That is because this is a reversible reaction as seen by the hydrolysis mechanism. We can interconvert between carbonyl and imine/enamine via acid catalysis and water. 

What do we get if we use a tertiary amine?

  • Tertiary amines have no N-H bond and therefore cannot form the first intermediate in imine and enamine reactions which is the hemiaminal. While good nucleophiles, NR3 groups will not react efficiently with aldehydes and ketones.  

Can we go from an imine to an enamine?

  • Yes, through a tautomerization. This can be acid or base catalyzed and the result is two constitutional isomers that can interconvert.  

What is the mechanism for the reverse reaction going from an imine or enamine back to the original carbonyl?

  • This is termed hydrolysis and the mechanism can be found above in the related topics section for enamines. The only difference for imines is that the first step involves protonation of the nitrogen to form the iminium cation.  

What were the 5 steps again for the mechanism?

  • The 5 steps for the imine and enamine mechanism are protonation, nucleophilic attack, proton transfer, elimination and deprotonation. 

Summary of Imine & Enamine Mechanism:

     I. Imine:

Imine MechanismImine Mechanism

Here is a summary of the imine mechanism. Notice the 5 steps involved: Protonation, Nucleophilic Attack, Proton Transfer, Elimination and Deprotonation.

     II. Enamine: 

Enamine MechanismEnamine Mechanism

Here is a summary of the enamine mechanism. The same 5 steps for the imine mechanism can be seen here, with the exception of the deprotonation step of the iminium cation where our conjugate base grabs a hydrogen from the alpha carbon.



Johnny Betancourt

Johnny got his start tutoring Organic in 2006 when he was a Teaching Assistant. He graduated in Chemistry from FIU and finished up his UF Doctor of Pharmacy last year. He now enjoys helping thousands of students crush mechanisms, while moonlighting as a clinical pharmacist on weekends.


Additional Problems
Write a detailed mechanism that explains the following reaction of 6 to furnish piperidine 7 and cyclohexanone 8. Show all intermediates! Transfer protons intramolecularly!
An iminium can be turned into an enamine in one step. Draw the mechanism of this below. Draw all the arrows to indicate movement of the all electrons, write all lone pairs, all formal charges, and all products.
Predict the product for the following reaction sequence.
Which carbonyl compounds cannot form an enamine with amine 1?
What product will result from the reaction shown? a. enamine b. imine c. hydroxylamine d. amino acid e. hydrazine
Draw the major organic product in the box provided. 
Indicate the order in which the intermediates would appear during the conversion of   1 into 2. 1) 1 → I → IV → II → 2 2) 1 → III → II → 2 3) 1 → V → III → I → IV → 2 4) 1 → V → III → II → 2 5) 1 → II → I → III → IV → 2  
Pick the corn chips scent.  
Provide a complete mechanism for the following transformation.
One of the following reactions are incorrect as written. Choose which reaction, A or B is incorrect and draw the correct product. Then fill in the 2 sentences below.    Reaction           is incorrect. The correct product should be a                      . Reaction           is correct because we formed a                     .   
The reaction of an amine with a carbonyl compound leads to an iminium ion, which can often convert into an imine or an enamine. Which combination below cannot form an enamine or an imine (i.e., must remain as an iminium ion)?
Which compound would react with  A to give product B?
What is the product of the following reaction?  
Provide the missing product. Show only one most preferred product. Consider only monosubstitution for EAS where appropriate.
Predict the product when cyclopentanecarbaldehyde reacts with phenylhydrazine (PhNHNH2) in the presence of an acid catalyst. 
Complete the following reaction by drawing the structure of the principal major product. Indicate relative stereochemistry where necessary. If there is no reaction, write NR.
What combination of reactants can be used to form the product shown?  
What combination of reactants can be used to form the product shown?
Complete the following reaction. Pay careful attention to the stereochemistry of the product.
Propose a synthetic pathway from the indicated starting material to the designated product
For the reaction below, draw the structure of the appropriate compound in the box provided. Indicate stereochemistry where it is pertinent.
Show your understanding of the following reaction by showing the mechanism and predicting the products.
Draw the organic products of the following reaction.
Click the "draw structure" button to launch the drawing utility. Draw the organic products formed in the following reaction.
Draw the structure(s) of the major organic product(s) of the following reaction.
Which of the following would give an enamine when reacted with acetone? 
Give the major product for the following reaction.
Choose the correct product for the reaction shown. 
What carbonyl compound and amine are formed by the hydrolysis for the compound below?
What is the product of the following reaction?  
Draw the organic products formed in the following reaction.
Draw the product of the following reaction.
Draw the product formed for the reaction of benzaldehyde with butylamine (butan-1-amine) in the presence of mild acid.
Draw the major product for each of the following reactions:
Draw the neutral organic product expected under these reaction conditions.  
Provide the major organic product(s) of the reaction below.