There are 4 major methods to create ethers. Most of these should look familiar in some way since they are variations of reactions we have used before.
The name given for the SN2 substitution of an oxide with an alkyl halide.
Concept: The Mechanism of Williamson Ether Synthesis.4m
Now I want to talk about ethers. It turns out that in organic chemistry one, you're going to be responsible to know four different methods to synthesize them. Some of these methods are going to be stuff that you already know from prior chapters. Some of it is going to be really related to other reactions you've learned, it's just going to be tweaked a little bit. Overall, this isn't so hard, you just have to keep track of the four reactions to make ethers.
Let's start off with the simplest one, which is called Williamson Ether Synthesis, which sounds complicated. You're thinking, “Oh man, another name that I have to memorize.” But really, this is an easy reaction. All this is going to be is an SN2 reaction of a primary or a methyl alkyl halide with an oxide base.
Now this is just a typical SN2 that we would use the flow chart for. You might be wondering, “Well, Johnny, why does it have that funky name?” Well, Williamson Ether Synthesis is just the name for that specific route that you take on the flow chart. Cool? So even if you forgot the name of this reaction, you would still know what to do just by using the flow chart.
Let's go ahead and talk about SN2 for a second. Remember that what does SN2 really require. A good backside. That's why primary and methyl alkyl halides are awesome at Williamson Ether Synthesis because they have a really good backside.
Well, what happens if I try to use a secondary or tertiary alkyl halide instead? Let's say that I'm like screw the primary alkyl halide. I want to start with my tertiary. Can we do that? No, we can't. Because remember that secondary and tertiary alkyl halides are sterically hindered in the back. What that means is that they're actually going to favor E2, not SN2.
So now that I've kind of explained the regents, let's just draw the mechanism. As you can see, what kind of alkyl halide am I starting off with? This would be primary. What kind of nucleophile do I have? Is it neutral or is it negatively charged? Well, in this case, this is negatively charged because it's going to dissociate into OEt negative.
Even if you didn't know what this was, we could just use the flow chart. According to the flow chart, the first question is is my nucleophile negative or neutral? It's negative. Two, is it one of my bulky bases? No. Three, what kind of alkyl halide do I have? Primary alkyl halide. Does that always favor a certain reaction? Yes, it favors SN2. Even if you didn't remember that this is Williamson Ether Synthesis, it's fine because you can just use the flow chart to figure it out.
Now we just have to draw the mechanism. The mechanism would be a backside attack. My OEt would kick out the Br and look what I get. I wind up getting a carbon with an O and then an ethyl group on the other side. Now, I'm just replacing the ethyl group – this is the thing that was Et before. I'm just drawing it out. But notice that look what functional group I have at the end. I have an ether. I was able to use an SN2 reaction just from the flow chart to make an ether. This is your first and probably most common form to make ethers in this chapter.
Good so far? Let's go ahead and move on to the second way to make ethers.
Condensation reactions join two smaller molecules together to form a single, larger molecule.
Concept: The Mechanism of Alcohol Condensation.5m
So another way to make ethers is through a reaction called Acid-Catalyzed Alcohol Condensation. I know this sounds really complicated, but it's not that bad. As you guys will learn later in orgo two, a condensation reaction is simply a reaction that takes two molecules and makes them into one bigger molecule. I'm just going to say it's a reaction that takes two smaller molecules and then it turns them into one bigger molecule. That's the definition of condensation.
What we're going to be doing here is we're going to be taking two alcohols, it's an alcohol condensation, so we're going to take two alcohols, we're going to put them together. We're going to condense them and they're going to turn into one ether.
How does this work? Let me just go ahead and just draw the mechanism for you. The way this works is you have alcohol in the presence of acid and heat. What's going to wind up happening is that the acid's going to protonate one of the alcohols.
Let's go ahead and just draw this part really quick. I've got my H3O+ that I'm going to write like this because it's easier to deprotonate that way. Same thing as H3O+, I'm just writing it a little bit different. So my OH is going to grab an H from the acid and what I'm going to wind up getting is something that looks like this. I have a protonated alcohol now.
Now what's going to happen is that that protonated alcohol just turned into a good leaving group. Water is a good leaving group. So my other equivalent of alcohol, the one that did not get protonated is going to do a backside attack on this good leaving group. We're basically going to get an SN2 reaction where I get this attacking that carbon and kicking out the good leaving group.
So now what we're going to wind up getting is – let me just draw it in the same colors that I used. The black alcohol that still has an H on it, but now that's going to be attached to the two-carbon chain from the red alcohol. On top of that, there's going to be a water that just left by itself. Does that make sense so far?
So we've got the black one attacking the red one. This looks like an ether, but we've got a problem. There's a formal charge. So what can we do about that formal charge? Remember, this is called acid catalyzed for a reason. That means that you always have to end up with the same amount of acid that you started off with because it's a catalyst. It can't be consumed or destroyed in the reaction.
What that means is that I use the water to pick up the proton. And what I'm going to wind up getting at the end is I'm going to get an ether plus the same H3O+ that I started off with. There you have it. We just condensed an ether out of alcohol.
Now there is going to be a significant limitation for this synthesis. Can anyone tell me? It's only going to yield a certain type of ether. Actually, there's a typo here that I will correct in your notes. This should not say alcohols. It should say ethers. But it's going to form only symmetrical ethers.
The reason is because we're always going to be reacting acid and alcohol and you're going to have an abundance of alcohol. What that means is that one molecule is going to react with another molecule of the same alcohol and you're going to wind up getting the same R groups on both sides. That's why I'm saying that it's symmetrical because you're always going to get the same R groups on both sides.
Sometimes you want that. For example, you wanted an asymmetrical ether. It has to be asymmetrical, maybe Williamson Ether Synthesis would be a better choice because that one it doesn't matter. You can just add R groups as you want.
So let's move on and keep talking about ethers.
Same reagents as oxymercuration, except with alcohol as the nucleophile instead of water.
Concept: The Mechanism of Alkoxymercuation.5m
Same reagents as acid-catalyzed hydration, except with alcohol as the nucleophile instead of water.
Concept: The Mechanism of Alkoxylation.5m
Problem: Predict the product of the following reaction.4m
Problem: Predict the product of the following reaction.6m
Draw the ether of molecular formula C 5H10O from BrCH2CH2CH2CH2CH2Br + NaOH in CH3OH.
For the reaction shown below, draw the structure of the major product(s). Where appropriate, write "No Reaction". Assume all chiral starting materials are optically pure. Show stereochemistry where appropriate. Indicate whether the product exists as a single enantiomer or a racemic mixture.
Predict the product of the following reaction.
Compare the following reactions and decide which reaction occurs fastest.
Device a synthetic pathway to form the following product.
Predict the product(s). If no reaction would occur, say so. Show stereochemistry where relevant. If more than one isomer or product would form, show all the ones which would form.