Problem: A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the F1 had lacerate leaves (jagged-edged leaves). Two F1 plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy?a. two genes, where one allele at a single locus is recessive lethal b. two genes, with a dominant allele at both loci c. two genes, with a dominant allele at either or both loci d. one gene, with codominant alleles at a single locus Give genotypes for all the plants in the P, F1, and F2 generations. Some generations will have more than one genotypePF1F2 (lacerate)F2 (normal)

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FREE Expert Solution

Given: F2 Generation

• 249 lacerate leaves

• 16 normal leaves

Phenotypic ratio: 15 lacerate : 1 normal


Recall: Duplicate Gene Interaction

: when the dominant allele of both gene loci produce the same phenotype without cumulative effect

: produces a phenotypic ratio of 15:1

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Problem Details

A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the F1 had lacerate leaves (jagged-edged leaves). Two F1 plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy?

a. two genes, where one allele at a single locus is recessive lethal 

b. two genes, with a dominant allele at both loci 

c. two genes, with a dominant allele at either or both loci 

d. one gene, with codominant alleles at a single locus 


Give genotypes for all the plants in the P, F1, and F2 generations. Some generations will have more than one genotype

P

F1

F2 (lacerate)

F(normal)