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Ch.17 - Chemical ThermodynamicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch.17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Spontaneous vs Nonspontaneous Reactions
Entropy Calculations
Entropy Calculations: Phase Changes
Third Law of Thermodynamics
Gibbs Free Energy
Gibbs Free Energy Calculations
Gibbs Free Energy And Equilibrium

The Third Law of Thermodynamics examines the state of entropy for a given substance at absolute zero.

Absolute Zero & Entropy

Concept #1: The entropy of a closed system can be related to its temperature.

Generally as the temperature of the system increases there will be an increase in the number of microstates and therefore an increase in entropy.

Example #1: All the statements are correct except:

a) greater number of molecular motion, greater number of possible microstates

b) a perfectly ordered system has more than 1 microstate

c) any system at a temperature above 0 K has a positive ∆S

d) perfect crystal exhibits no molecular motion

Concept #2: The Boltzmann Equation allows for the calculation of entropy by examining the different energetic configurations of a compound.

Example #2: Consider a system with a total of 3 x 1026 number of microstates, what is the entropy of such a system?

Practice: A brand new deck of cards which hasn’t been shuffled yet, possesses only one arrangement. Another, older deck has been shuffled and possesses 8 × 1067 arrangements. Calculate and compare entropies of each deck.