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Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Solubility Rules
Molecular Equations
Gas Evolution Equations
Solution Stoichiometry
Complete Ionic Equations
Calculate Oxidation Numbers
Redox Reactions
Balancing Redox Reactions: Acidic Solutions
Balancing Redox Reactions: Basic Solutions
Activity Series
Additional Guides
Oxidation Reduction (Redox) Reactions (IGNORE)
Oxidation Number (IGNORE)
Net Ionic Equation (IGNORE)

Solution Stoichiometry deals with stoichiometric calculations in solutions that involve volume and molarity.

Solution Stoichiometry

Concept #1: Solution Stoichiometry

Use the solution stoichiometric chart when dealing with calculations involving molarity and/or volume. 

Example #1: How many moles of hydrogen gas were produced when 38.74 mL of 0.275 M H2O reacts with excess sodium?

Practice: How many milliliters of 0.325 M HCl are needed to react with 16.2 g of magnesium metal? 

2 HCl (aq) + Mg (s) → MgCl2 + H2 (g)

Practice: What is the molar concentration of a hydrobromic acid solution if it takes 34.12 mL of HBr to completely neutralize 82.56 mL of 0.156 M Ca(OH)­2

2 HBr (aq) + Ca(OH)2 (aq)  → CaBr2 (aq) + 2 H2O (l)

Practice: Consider the following balanced chemical equation: 

H2O+ 2 MnO4 + 3 SO32-  → 2 MnO2 + 3 SO42-+ 2 OH

How many grams of MnO2 (MW: 86.94 g/mol) will be created when 25.0 mL of 0.120 M MnO4 (MW: 118.90 g/mol) reacts with 32.0 mL of 0.140 M SO32- (MW: 80.07 g/mol).