# Problem: An 8.65-g sample of an unknown group 2A metal hydroxide is dissolved in 85.0 mL of water. An acid-base indicator is added and the resulting solution is titrated with 2.50 M HCl (aq) solution. The indicator changes color signaling that the equivalence point has been reached after 56.9 mL of the hydrochloric acid solution has been added.What is the molar mass of the metal hydroxide?

###### FREE Expert Solution

Recall that at the equivalence point of a titration:

Also, recall that:

• moles = molarity × volume
• moles = molarity × molar mass

For acids: Multiply by the number of H+ ions

For bases: Multiply by the number of OH, H, O2–, or NH2 ions

This means:

$\overline{){\left(\mathbf{MV}\right)}_{{\mathbf{acid}}}{\mathbf{=}}{\mathbf{2}}\mathbf{\left(}{\mathbf{moles}}_{\mathbf{base}}\mathbf{\right)}}$

###### Problem Details

An 8.65-g sample of an unknown group 2A metal hydroxide is dissolved in 85.0 mL of water. An acid-base indicator is added and the resulting solution is titrated with 2.50 M HCl (aq) solution. The indicator changes color signaling that the equivalence point has been reached after 56.9 mL of the hydrochloric acid solution has been added.

What is the molar mass of the metal hydroxide?