Sr(OH)2 (aq) + 2 HNO3 (aq) → Sr(NO3)2 (aq) + 2 H2O (l)
= 0.1233 mol Sr(OH)2
= 0.0126 mol HNO3
A solution is made by mixing 15.0 g of Sr(OH)2 and 60.0 mL of 0.210 M HNO3.
Calculate the concentration of Sr2+ ion remaining in solution.
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