Problem: A solution is made by mixing 15.0 g of Sr(OH)2 and 60.0 mL of 0.210 M HNO3.Calculate the concentration of Sr2+ ion remaining in solution.

FREE Expert Solution

Sr(OH)2 (aq) + 2 HNO3 (aq)  Sr(NO3)2 (aq) + 2 H2O (l)


Step 1

15.0 g Sr(OH)2 × 1 mol Sr(OH)2121.63 g Sr(OH)2  = 0.1233 mol Sr(OH)2


60.0 mL ×10-3 L1 mL×0.210 mol HNO31 L = 0.0126 mol HNO3


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Problem Details

A solution is made by mixing 15.0 g of Sr(OH)2 and 60.0 mL of 0.210 M HNO3.

Calculate the concentration of Sr2+ ion remaining in solution.

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