Problem: A solution of 116 mL of 0.180 M KOH is mixed with a solution of 260 mL of 0.210 M NiSO4.What is the concentration of SO42- that remains in solution?

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Step 1

2 KOH + NiSO4 → Ni(OH)2 + K2SO4

116 mL ×1×10-3 L1 mL ×0.180 mol KOH1 L×1 mol K2SO42 mol KOH = 0.01044 mol K2SO4


260 mL ×1×10-3 L1 mL ×0.210 mol NiSO41 L×1 mol K2SO41 mol NiSO4 = 0.0546 mol K2SO4

KOH → limiting reactant


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Problem Details

A solution of 116 mL of 0.180 M KOH is mixed with a solution of 260 mL of 0.210 M NiSO4.

What is the concentration of SO42- that remains in solution?

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