# Problem: A solution of 116 mL of 0.180 M KOH is mixed with a solution of 260 mL of 0.210 M NiSO4.What is the limiting reactant?

###### FREE Expert Solution

We’re being asked to determine the limiting reactant for the reaction that occurs when 116 mL of 0.180 M KOH is mixed with a solution of 260 mL of 0.210 M NiSO4.

For this problem, we need to do the following steps:

Step 1: Determine the products of the reaction.

Step 2: Write and balance a chemical equation for the given reaction.

Step 3: Determine the limiting reactant

Recall that the limiting reactantis the reactant that forms the less amount of product.  This is because once the limiting reactant is all used up, the reaction can no longer proceed and make more products.

Step 1: Since KOH and NiSO4 are ionic compounds, they form ions when dissociating in water. The dissociation of the two compounds is as follows:

For KOH:

The hydroxide ion, OH, has a charge of –1. Potassium, K is from Group 1 so it has a charge of +1:

KOH(aq)  K+(aq) + OH(aq)

For NiSO4:

The sulfate ion, SO42–, has a charge of –2. Nickel, Ni then has a charge of +2:

NiSO(aq)  Ni2+(aq) + SO42–(aq)

**Recall that for ionic compounds with the same numerical charge, the subscript is not written ###### Problem Details

A solution of 116 mL of 0.180 M KOH is mixed with a solution of 260 mL of 0.210 M NiSO4.

What is the limiting reactant?