# Problem: The distinctive odor of vinegar is due to acetic acid, CH3COOH, which reacts with sodium hydroxide in the following fashion:CH3COOH(aq) + NaOH(aq)(l) + NaC2H3O2 (aq)You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.If 3.55 mL of vinegar needs 43.0 mL of 0.130 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.60 qt sample of this vinegar?

###### FREE Expert Solution

Recall that at the equivalence point of a titration:

Also, recall that:

• moles = molarity × volume
• moles = mass/ molar mass

This means:

$\overline{){\mathbf{\left(}\mathbf{MV}\mathbf{\right)}}_{{\mathbf{acid}}}{\mathbf{=}}{\left(\mathbf{MV}\right)}_{{\mathbf{base}}}}$

Solving for Macid:

= 1.575 M

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###### Problem Details

The distinctive odor of vinegar is due to acetic acid, CH3COOH, which reacts with sodium hydroxide in the following fashion:
CH3COOH(aq) + NaOH(aq)(l) + NaC2H3O2 (aq)

You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.

If 3.55 mL of vinegar needs 43.0 mL of 0.130 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.60 qt sample of this vinegar?