Problem: You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.If 26.2 mL of AgNO3 is needed to precipitate all the Cl- ions in a 0.780-mg sample of KCl (forming AgCl), what is the molarity of the AgNO3 solution?

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AgNO3 + KCl → AgCl + KNO3


0.780 mg KCl ×1×10-3 g KCl1 mg KCl×1 mol KCl74.55 g KCl×1 mol AgNO31 mol KCl

 = 1.05x10-5 mol AgNO3


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Problem Details

You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem.

If 26.2 mL of AgNO3 is needed to precipitate all the Cl- ions in a 0.780-mg sample of KCl (forming AgCl), what is the molarity of the AgNO3 solution?

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