Problem: What volume of 0.132 M HCl is needed to neutralize 2.76 g of Mg(OH)2?

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What volume of 0.132 M HCl is needed to neutralize 2.76 g of Mg(OH)2?

Reaction:  2 HCl + Mg(OH)2 → MgCl2 + H2O


Calculate moles HCl need to react with Mg(OH)2:

molar mass Mg(OH)2 = 58.321 g/mol

moles HCl=2.76 g Mg(OH)2×1 mol Mg(OH)258.321 g Mg(OH)2×2 mol HCl1 mol Mg(OH)2

moles HCl = 0.09464 mol


Calculate the volume of HCl solution needed:

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What volume of 0.132 M HCl is needed to neutralize 2.76 g of Mg(OH)2?

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Based on our data, we think this problem is relevant for Professor Guimerans' class at LONESTAR.