Problem: Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25 oC.Calculate the molarity of a solution of acetic acid made by dissolving 21.00 mL of glacial acetic acid at 25 oC in enough water to make 260.0 mL of solution.

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Step 1. mol acetic acid

molar mass CH3COOH = 60.052 g/mol

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Problem Details

Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25 oC.

Calculate the molarity of a solution of acetic acid made by dissolving 21.00 mL of glacial acetic acid at 25 oC in enough water to make 260.0 mL of solution.

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