Ch.4 - Chemical Quantities & Aqueous ReactionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Enter a balanced equation for the reaction of Na2S and CdSO4.

Solution: Enter a balanced equation for the reaction of Na2S and CdSO4.

Problem

Enter a balanced equation for the reaction of Na2S and CdSO4.

Solution
  • Reaction between this compound is a double displacement reaction where counterions are being switched

  • Na2S (aq) will dissociate as Na+ (aq) and S2- (aq) while CdSO4 (aq) as Cd2+ and SO42- (aq). Recall that for ionic compounds, the charge of the ion goes to the subscript of the counter ion

  • Switching the counterions, products will appear as: Na2SO4 and CdS. 

  • In aqueous media, we need to determine if the products will  be soluble (aq) or insoluble (s) by using the solubility rules

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